Select Page The bars of varying sections, material properties, and dimensions, that are subjected to axial loads can be analyzed to determine their corresponding stress and strain values.

The analysis is performed based on the fundamental equation from Hooke’s law, that relates the stress (f) and the strain (e) by

f = e.E ———-Eq.1

Where, ‘E’ is the modulus of elasticity. Here the analysis of strain or deformation of bars of varying sections is explained briefly.

## Analysis of Bars of Varying Sections

Consider a bar of different length, area of cross-section and diameter, subjected to a axial load of ‘P’ as shown in figure-1.

The stress and deformation of length caused in each of the sections of the bar are different, even if the axial load acting on the bar is the same. The derivation is followed by the principle that,

Total Change in length, dL = Sum of Change in length of Section 1, Section 2 and Section 3.

dL = dL1 + dL2 +dL3 ———-Eq.2

### 1. Analysis of Section-1

Stress in Section 1,

f1 = Load/Area of Section-1 = P/A1

Strain in Section 1,

e1 = Change in length/Original Length = dL1/L1 = f1/E = P/(A1E) [From Eq.1]

Hence, Change in Length dL1=PL1/(A1E) ———-Eq.3

### 2. Analysis of Section-2

Stress in Section 2,

f2 = Load/Area of Section-2 = P/A2

e2 = Change in length/Original Length = dL2/L2 = f2/E =P/(A2E) [From Eq.1]

Hence, Change in Length dL2= PL2/(A2E) ———-Eq.4

### 2. Analysis of Section-2

Stress in Section 3,

f3 = Load/Area of Section-3 = P/A3

e3 = Change in length/Original Length = dL3/L3 = f3/E=P/(A3E) [From Eq.1]

Hence, Change in Length dL3= PL3/(A3E) ———-Eq.5

From Eq.2,

dL = dL1 + dL2 +dL3

Therefore, Eq.3 + Eq.4 + Eq.5,

dL = dL1 + dL2 +dL3 = PL1/(A1E) +PL2/(A2E)+ PL3/(A3E) 